iv
Decide the number of valence electrons in each of the neutral atoms. carbon: nitrogen: oxygen: chlorine: sulfur:
2 answers:
4 0
Explanation:
Valence electrons -
It refers to the number of electrons that are present at the very last shell of the atom , is referred to as the valence electrons .
From the question ,
Carbon -
Diminutive number = 6
electronic configuration is written as -two, 4 .
Hence ,
Valence electrons =4 .
Nitrogen -
Atomic number = 7
electronic configuration is written as - 2, five .
Hence ,
Valence electrons = 5 .
Oxygen -
Atomic number = 8
electronic configuration is written as -two , 6.
Hence ,
Valence electrons =vi .
Chlorine -
Atomic number = 17
electronic configuration is written as -2, 8, seven .
Hence ,
Valence electrons = vii .
Sulfur -
Atomic number = 16
electronic configuration is written as -two , viii, vi
Hence ,
Valence electrons =half dozen .
4 0
Answer: C = 4 valence electrons
Due north = v valence electrons
O = half-dozen valence electrons
Cl = 7 valence electrons
S = half-dozen valence electrons
Caption: Refer to each electron configuration:
C - 1s², 2s²,2p² valence e- add the exponents on the highest free energy level which is period 2. Then ii+2=iv
N - 1s²,2s²,2p³ add the exponent in the 2nd orbital: two+three =5 valence electrons
O - 1s²,2s²,2p⁴ add the exponents in the 2nd orbital: two +4 = 6 valence electrons
Cl- 1s²,2s²,2p5 add the exponents in the 2nd orbital: 2 +5 = 7 valence electrons.
S- 1s²,2s²,2p⁴ add the exponents in the second orbital: two + 4= 6 valence electrons.
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Chlorine Number Of Valence Electrons,
Source: https://1answer.guru/questions/5287617-determine-the-number-of-valence-electrons-in-each-of-the-neutral.html
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